Themes > Science > Physics > Electromagnetism > Electrostatics > Capacitors & Dielectrics > Capacitors and Dielectrics > Gauss Law in Dielectrics > Example Problem: The Spherical Capacitor

A metallic sphere of radius R is surrounded by a concentric dielectric shell of inner radius R, and outer radius 3R/2. This is surrounded by a concentric, thin, metallic shell of radius 2R (see Figure 10). The dielectric constant of the shell is [kappa]. What is the capacitance of this contraption ?

Suppose the charge on the inner sphere is Qfree. The electric field inside the dielectric can be determined by applying Gauss' law for a dielectric (eq.(50)) and using as the integration volume a sphere of radius r (where R < r < 3R/2)

(51)

The electric field in this region is therefore given by

(52)

 

Figure 10. Problem 25.

The electric field in the region between 3R/2 and 2R can be obtained in a similar manner, and is equal to

(53)

Using the electric field from eq.(52) and eq.(53) we can determine the potential difference [Delta]V between the inner and outer sphere:

 

(54)

The capacitance of the system can be obtained from eq.(54) using the definition of the capacitance in terms of the charge Q and the potential difference [Delta]V:

 

(55)


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