For the calculation of the electrostatic potential U of a charge
density
one
can use the equation (in atomic units)
Inserting the Laplace expansion
with the abbreviations
,
,
and
and the complex spherical harmonics
in the phase convention of Condon and Shortley
[126]
as defined in [127],
p. 3, Eq. (1.2-1), and interchanging the order of integration and
summation yields
This can be interpreted as orthogonal
expansion in the complete orthonormal system of
spherical harmonics.
If the charge density vanishes outside of a
sphere of radius a with center at the origin and
if r>a
holds then r>r'
is satisfied for all
for which
holds, and the relation
follows.
Introduction of the multipole moments
allows to represent the potential by an
infinite series of the form
that is usually called the multipole
expansion. In particular, for a charge distribution
that is
invariant under rotations with axis
, the multipole moments have the form
and the addition theorem
of the spherical harmonics yields an
expansion in Legendre polynomials
This form of the electrostatic potential is
also implied by the fact that the Laplace
equation
holds outside of a charge distribution. The only solutions of
this
equation for
in spherical coordinates are linear combinations of irregular
solid
harmonics
and thus, taking rotational symmetry
around the direction
into account, only linear combinations of
occur in the multipole expansion of U where
is the angle between the position vector and
the direction
.
If the charge distribution does not have
compact support in
, the above multipole expansions
only hold approximately for large
. In this case, the inequality r>r' does not
hold for
all
for which
.
The difference between the exact potential U
and the multipole expansion
in Eq. (6)
is given by
Because of
the difference
can also be represented as
If
decays sufficiently rapidly for large arguments, the contributions with
angular
momentum quantum number
to the difference
will go to zero for large r
(unless they vanish anyway by
symmetry). In the case of the example
with
, only the term with
survives the
angular integration and one obtains
Hence, the difference
vanishes for large r exponentially in this simple
model example.
Note that the multipole expansion
for
is a solution of the Laplace equation
.
But the exact electrostatic potential U satisfies the Poisson
equation (atomic units)
This implies that also the difference
is a solution of this Poisson equation.
A further consequence
is that the
multipole expansion can only be a good approximation
to U where the
charge density is small, i.e., for large distances from the origin.
An advantage of the multipole expansion is
that the moments
or
, respectively, to a
given charge distribution
can be computed once and for all, and then, the multipole
approximation
of
can be computed very easily for very many arguments
.
The exact expansion (3)
of
on the other hand is more demanding computationally.
It requires the
calculation of the integrals
that depend also on the distance r
to the expansions centre. If the charge density
is rotationally
symmetric around the direction
, then in analogy to Eq. (7)
we have
and hence, the expansion (3)
simplifies to
This corresponds to the cylindrical
symmetry of the problem since only the coordinates r
and
with
enter. Thus, one obtains an expansion in Legendre
polynomials that may or
may not converge rapidly.
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