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Gauss's law can derive the E-field for the following geometries:
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A spherically
symmetric charge distribution, e.g. a point charge.
The Gaussian surface should be a sphere. The area of the surface is 4pr2,
so Gauss's law becomes:
where Q(r) is the charge inside the surface. For a point
charge, Q(r) is the total charge, whereas for a uniform
charge density r (charge per unit volume) the charge inside
the surface is:
Thus for a uniform sphere of charge, the electric field is zero at r=0,
and grows linearly in r inside the sphere, while outside the
sphere the electric field is of the same form as Coulomb's law.
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A large plate with
uniform charge density.
Consider the plate below, which we will assume is infininte ( a good
assumption if you are close to the plate) and has a charge per unit
area, s.

Gauss's law states (remember the field leaves through both sides):
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Two oppositely
charged parallel plates.
If there were two plates with opposite charge, the electric field
would be double this value in between the plates, ,and
zero outside the plates.
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An infinite line
charge.
Drawing a cylinder of length L around an infinite wire, which
has a charge per unit length of l, will trap a charge inside of Q=lL,
and the area through which the flux leaves is 2prL.
Gauss's law then states:
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