| Themes > Science > Physics > Molecular Physics > Molecular Spectra > Molecular Spectra |
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The (100) and (020) vibrational levels depopulate when they relax rather quickly into lower vibrational levels, particularly the (010) mode. The CO2 molecule transfers energy from these lower vibrational levels to the He atoms through collisions. Since the infrared laser transitions are relatively slower than this depopulation mechanism, a population inversion results.
If the energy difference between the lowest (001) state and the lowest (100) state is E0, then the energy of the transition between the J=7 (001) state and the J=6 (100) state will be of energy:
Likewise, transitions where the change in J is +1, the energy released will be:
Moreover, we should see in the laser emission two distinct bands, each having P and R branches, corresponding to the series of transitions from the (001) to the (100) and from the (001) to the (020) vibrational modes. Because the difference between adjacent rotational levels increases as J increases, the separation between emission lines in the P and R branch will increase as J increases. The branches will be centered around frequency v0 (corresponding to E0). According to Maxwell-Boltzmann statistics, the distribution of molecules in rotational states should follow the relation:
where G(j) is the degeneracy of each state, which happens to be 2J+1. So, the population of molecules in the Jth rotational state should be proportional to:
This will give a distribution that looks like this:
When the excited CO2 levels are populated by collisions with N2 the levels will be populated according to this relation. Laser transitions will be most probable from the rotational states that have maximum population (i.e. the maximum on the Boltzmann curve) As a result, each branch in the emission will be curved similarly to the Boltzmann curve. |
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