This is a classic example of interference effects in light waves. Two
light rays pass through two slits, separated by a distance d and
strike a screen a distance, L , from the slits, as in Fig. 22.10.
Figure 22.10:
Double slit diffraction
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If d < < L then the difference in path length r1
- r2 travelled by the two rays is approximately:
r1 - r2
dsin 
where
is approximately equal to the angle that the rays make relative to a
perpendicular line joining the slits to the screen.
If the rays were in phase when they passed
through the slits, then the condition for constructive interference at the
screen is:
dsin
= m
,m =
1,
2,...
whereas the condition for destructive
interference at the screen is:
dsin
= (m + )
,m =
1,
2,...
The points of constructive interference will
appear as bright bands on the screen and the points of destructive
interference will appear as dark bands. These dark and bright spots are
called interference fringes. Note:
- In the case that y , the distance
from the interference fringe to the point of the screen opposite the
center of the slits (see Fig.22.10) is much less than L ( y
< < L ), one can use the approximate formula:
sin
y/L
so that the formulas specifying the y
- coordinates of the bright and dark spots, respectively are:
y Bm
=
brightspots
y Dm
=
darkspots
The spacing between the dark spots is
y
= 
- If d < < L then the
spacing between the interference can be large even when the wavelength
of the light is very small (as in the case of visible light). This
give a method for (indirectly) measuring the wavelength of light. (See
Ex.6 at the end of this Chapter.)
- The above formulas assume that the slit
width is very small compared to the wavelength of light, so that the
slits behave essentially like point sources of light.
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